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Which of the following is an equation of the line tangent to the graph of x^2 - 3xy = 10 at the point (1, -3)?

Respuesta :

Answer:

Step-by-step explanation:

slope = m = y'

x² - 3xy = 10

2x - 3y - 3xy' = 0

at (1, -3)

2(1) - 3(-3) - 3(1)y' = 0

2 + 9 = 3y'

y' = 11/3

equation of tangent:

y = -3 + (11/3) (x - 1) = 11x/3 - 20/3

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