If a 10.4 kg block rests on a rough horizontal table with a coefficient of friction =0.15, then what is the resulting force of friction on the block?

Respuesta :

The resulting force of friction on the block is mathematically given as

F=1.56

What is the resulting force of friction on the block?

Question Parameters:

If a 10.4 kg block rests on a rough horizontal table with a coefficient of friction =0.15

Generally, the equation for the Frictioval force   is mathematically given as

F=uN

Where

u=coefficient of friction

N=normal force

F=Frictional force

In conclusion, the resulting force of friction on the

F=10.4*0.15

F=1.56

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