The resulting force of friction on the block is mathematically given as
F=1.56
Question Parameters:
If a 10.4 kg block rests on a rough horizontal table with a coefficient of friction =0.15
Generally, the equation for the Frictioval force is mathematically given as
F=uN
Where
u=coefficient of friction
N=normal force
F=Frictional force
In conclusion, the resulting force of friction on the
F=10.4*0.15
F=1.56
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