. Given: Diameter XY of circle k (O) , RS ∥ TU , XY bisects rs at m xy intersects tu at n. prove n is midpoint of TU

The diameter XY divides the circle into equal segments
It is true that point N is the midpoint of TU
Given that:
The diameter of the circle is line XY
RS || TU
The statement RS || TU means that lines RS and lines TU are parallel lines.
Also from the question, we have:
XY bisects RS at M
This means that:
[tex]RS \sim TU[/tex] --- line RS and TU are similar lines
Express as ratio
[tex]RM : MS \sim TN : NU[/tex]
Point M is the midpoint of line RS, because the line XY passes through point M on line RS.
By comparing the points on the statement [tex]RM : MS \sim TN : NU[/tex]
Point M corresponds to point N, point R corresponds to point T and point S corresponds to point U
This means that:
Point N is the midpoint of TU
Hence, it is true that point N is the midpoint of TU
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