. Given: Diameter XY of circle k (O) , RS ∥ TU , XY bisects rs at m xy intersects tu at n. prove n is midpoint of TU

Given Diameter XY of circle k O RS TU XY bisects rs at m xy intersects tu at n prove n is midpoint of TU class=

Respuesta :

The diameter XY divides the circle into equal segments

It is true that point N is the midpoint of TU

How to prove the midpoint of TU

Given that:

The diameter of the circle is line XY

RS || TU

The statement RS || TU means that lines RS and lines TU are parallel lines.

Also from the question, we have:

XY bisects RS at M

This means that:

[tex]RS \sim TU[/tex] --- line RS and TU are similar lines

Express as ratio

[tex]RM : MS \sim TN : NU[/tex]

Point M is the midpoint of line RS, because the line XY passes through point M on line RS.

By comparing the points on the statement [tex]RM : MS \sim TN : NU[/tex]

Point M corresponds to point N, point R corresponds to point T and point S corresponds to point U

This means that:

Point N is the midpoint of TU

Hence, it is true that point N is the midpoint of TU

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