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Michael wants to replace the wooden floor at his gym. The floor is in the shape of a rectangle. Its length is 40 feet and its width is 30 feet. Suppose wood flooring costs $12 for each square foot. How much will the wood flooring cost for the floor?

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Starrysoul100

[tex]\bold{\huge{\underline{ Solution }}}[/tex]

Given :-

  • Michael wants to replace the wooden floor at his gym.
  • The floor is rectangle in shape having length and breath are 40 feet and 30 feet
  • The cost of wooden flooring is $12 for each square foot

To Find :-

  • We have to find the total cost of wooden flooring

Procedure :-

  • As it was given in the question that Michael wants to replace the wooden floor at his gym. Whose length and breath are 40 feet and 30 feet.
  • Step - 1 :- You have to find the area of wooden floor because it include entire surface of the floor
  • Step - 2 :- After finding the area of the wooden floor then find the product of the cost for each feet and area of the wooden floor

Let's Begin :-

Michael wants to replace the wooden floor at his gym.

  • The dimensions of the wooden floor are 40 feet and 30 feet

We know that,

Area of rectangle

[tex]\bold{\pink{ = Length {\times} Breath }}[/tex]

Subsitute the required values,

[tex]\sf{ = 40 {\times} 30 }[/tex]

[tex]\bold{ = 1200\: ft^{2}}[/tex]

Thus, The area of the floor is 1200 ft²

Now,

We have to find the total cost of flooring

  • The cost of flooring for each square feet = $12

Therefore,

Total cost of wooden flooring

[tex]\sf{ = 12 {\times} 1200 }[/tex]

[tex]\bold{ = 14400 \: dollars }[/tex]

Hence, The total cost of wooden flooring is $14400 .

Answer:

$14,400 is the correct answer.

Step-by-step explanation:

Given:

  • Length of Rectangle is 40 feet.
  • Breadth of Rectangle is 30 feet.
  • Cost of wood flooring for each square foot is $12.

[tex] \: [/tex]

To Find:

  • What will wood flooring cost for the floor?

[tex] \: [/tex]

Solution:

As, we know:

[tex] \bigstar \quad{ \large{ \rm{ \boxed{ \green{Area_{(Rectangle)} = Length × Breadth }}}}} \quad \bigstar[/tex]

[tex]{ \large{ \longrightarrow{ \rm{ Area_{(Rectangle)} = 40 \times 30}}}}[/tex]

[tex]{ \large{ \longrightarrow{ \rm{Area_{(Rectangle)} ={ \boxed{ \pink{ \rm{ 1200 \: {ft}^{2} }}}}}}}}[/tex]

Hence, Area of floor is 1200 ft².

Now,

Cost of wood flooring per ft² = $12

[tex]{ \large{ \dashrightarrow{ \rm{Cost_{(Wood \: flooring)} = 12 \times 1200 }}}}[/tex]

[tex]{ \large{ \dashrightarrow{ \rm{ Cost_{(Wood \: flooring)} ={ \boxed{ \pink{ \rm{ 14400 }}}}}}}}[/tex]

Hence, the cost of wood flooring is $14400

_________________________

Learn More:

[tex]\boxed{\begin {array}{cc}\\ \dag\quad \Large\underline{\bf{ \red{ Formulas\:of\:Areas:-}}}\\ \\ \star\sf Square=(side)^2\\ \\ \star\sf Rectangle=Length\times Breadth \\\\ \star\sf Triangle=\dfrac{1}{2}\times Base\times Height \\\\ \star \sf Scalene\triangle=\sqrt {s (s-a)(s-b)(s-c)}\\ \\ \star \sf Rhombus =\dfrac {1}{2}\times d_1\times d_2 \\\\ \star\sf Rhombus =\:\dfrac {1}{2}d\sqrt {4a^2-d^2}\\ \\ \star\sf Parallelogram =Base\times Height\\\\ \star\sf Trapezium =\dfrac {1}{2}(a+b)\times Height \\ \\ \star\sf Equilateral\:Triangle=\dfrac {\sqrt{3}}{4}(side)^2\end {array}}[/tex]

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