contestada

6. Hagrid has been breeding his pets again. He is breeding his pet Flutty (a large 3-1
slobbering dog) in an attempt to get 4 headed drooling dogs. Hagrid knows that having 3 heads
is dominant (H), while the presence of 4 heads is the result of a recessive allele (h). Drooling is a
dominant trait (D), while dry mouth is a recessive trait (d). What is the expected frequency of
drooling, 4-headed dogs in if Hagrid crosses 2 dogs that are heterozygous for both traits?

Respuesta :

lheduardomarques

The expected frequency is a phenotypic ratio of 3:1, where 75% of individuals are dominant and 25% are receptive, but the genotypic ratio is 1:2:1, as 25% of children are Hd, 50% HD, and 25 % hd.

How to calculate frequencies?

When you want to calculate the number of gametes that an individual produces, the formula 2 to the power of n is used, where n represents the number of pairs of hybrid genes (heterozygous) existing in the genotype.

Multiplication of the number of genotypes obtained, resulting in a total of different genotypes in the generation resulting from the cross performed:

  • Hh = 3
  • Dd = 3
  • T= 6

To determine the number of phenotypes, the same genotype calculation is performed, that is, the characteristics are separated, analyzed and the number of phenotypes will be multiplied at the end.

  • G = 4
  • T=24

With this information, we can conclude that the expected frequency is a phenotypic ratio of 3:1, where 75% of the individuals are dominant and 25% are receptive, but the genotypic ratio is 1:2:1, since 25% of the children are Hd, 50% DH and 25% hd.

Learn more about phenotypic brainly.com/question/20730322

Otras preguntas