Nqobile05
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A block of mass 5kg on a plane that is inclined at 30° to the horizontal,calculate the components of the block's weight​

Respuesta :

Answer:

W = 5 kg * 9.8 m/s^2 = 49 N          weight of 5 kg

Fy = W cos 30 = W √3 / 2        component of block's weight that is perpendicular to the plane (N the normal force)

Fx = W sin 30 = W / 2       component of block's weight that is along the plane

Fy = 42.4 N

Fx = 24.5 N

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