LM is midsegment of trapezoid ABCD. If AB=46 and DC=125, what is LM?

Answer:
LM=85.5.
Step-by-step explanation:
A trapezoid mid segment connects the midpoints of the two congruent sides of the trapezoid it is parallel to the pair of parallel sides.
The length of the mid segment is the sum of the two bases divided by 2.
In the figure LM is the mid segment :
LM=[tex]\frac{AB+CD}{2}[/tex]
It is given AB=46 and DC=125 ,
Substituting these values:
LM=[tex]\frac{46+125}{2}=85.5[/tex]
LM= 85.5.
The sum of the length of the base of trapezoid is equal to the twice the length of the midsegment. The length of the midsegment LM is 85.5 units.
The length of the midsegment of trapezoid has to be find out.
The midsegment of trapezoid is parallel to both the base. The sum of the length of the base of trapezoid is equal to the twice the length of the midsegment.
Given information-
LM is midsegment of trapezoid ABCD.
The length of the line segment AB is 46 units.
The length of the line segment DC is 125 units.
By the definition of midsegment of trapezoid,
[tex]2LM=AB+DC\\LM=\dfrac{AB+DC}{2} \\LM=\dfrac{46+125}{2} \\LM=\dfrac{171}{2} \\LM=85.5[/tex]
Hence the length of the midsegment LM is 85.5 units.
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