Answer: [tex]y=x^2-6x+45[/tex]
Step-by-step explanation:
The equation of parabola in standard form is given by :-
[tex]y=ax^2+bx+c[/tex]
Given : The vertex form of the equation of a parabola is [tex]y = (x - 3)^2 + 36.[/tex]
Using identity:
[tex](a-b)^2=a^2-2ab+b^2[/tex]
The above equation can be written as :
[tex]y =x^2-2(3)x+(3)^2 +36\\\\\Rightarrow\ y=x^2-6x+9+36\\\\\Rightarrow\ y=x^2-6x+45[/tex]
Hence, the standard form of the equation = [tex]y=x^2-6x+45[/tex]
