we know that
The compound interest formula is equal to
[tex]A=P(1+\frac{r}{n})^{nt}[/tex]
where
A is the Final Investment Value
P is the Principal amount of money to be invested
r is the rate of interest in decimal
t is Number of Time Periods
n is the number of times interest is compounded per year
in this problem we have
[tex]t=4\ years\\ P=\$5,350\\ r=0.035\\n=1[/tex]
substitute in the formula above
[tex]A=5,350(1+\frac{0.035}{1})^{1*4}=\$6,139.25[/tex]
therefore
the answer is the option D
[tex]\$6,139.25[/tex]
