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A gargoyle statue falls off the side of a building from a height of 75 m how fast is the statue moving after 1.75 seconds

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MissPhiladelphia
This problem right here is a free fall problem. We are asked to find the velocity of the statue falling after a certain time. We use the formulas:

t = sqrt(2y/g)
and
v = sqrt(2gy)

We calculate as follows:
1.75 = sqrt(2(y)/9.81)
y = 15.02

v = sqrt(2(9.81)(15.02))
v = 17.17 m/s

Answer:

17.15 m/s

Explanation:

As the statue falls from a height so initial velocity is zero.

U = 0, t = 1.75 s, V = ?

Use first equation of motion,

V = U + at

Here a is acceleration due to gravity.

V = 0 + 9.8 × 1.75

V = 17.15 m/s

Thus, the velocity of statue after 1.75 second is 17.15 m/s.

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