Respuesta :
Answer:
Reflection across the y-axis and a dilation by a factor of 2.
Step-by-step explanation:
Comparing the points from the pre-image, ABC, to the image, A'B'C', we see that both x- and y-coordinates seem to be doubled from the pre-image to the image. However, the sign of the x-coordinates in the image is different; this means that the x-coordinates are negated. A reflection across the y-axis will negate the x-coordinates.
To double both the x- and y-coordinates, we would then apply a dilation by a factor of 2, as the scale factor gets multiplied by every coordinate.
The [tex]\Delta ABC[/tex] gets reflection across Y-axis and a dilation by a scale factor of 2.
Given,
The coordinates of [tex]\Delta ABC[/tex] are [tex]A(-3,2)[/tex], [tex]B(-1,0)[/tex] and [tex]C(-2,-1)[/tex] .
The coordinates of [tex]\Delta A'B'C'[/tex] are [tex]A'(6,4)[/tex], [tex]B'(2,0)[/tex] and [tex]C'(4,-2)[/tex] .
We have to find which transformation is performed on [tex]\Delta ABC[/tex] to form [tex]\Delta A'B'C'[/tex].
Now take a look on the coordinates of vertex of each triangle we found that each coordinate of [tex]\Delta A'B'C'[/tex] is doubled and the sign of abscissa of each coordinate of [tex]\Delta A'B'C'[/tex] is changed with respect to the coordinates of [tex]\Delta ABC[/tex].
Since the sign of abscissa of any coordinate of point is only changed when we reflect the point across Y-axis.
Hence the [tex]\Delta ABC[/tex] gets a reflection across Y-axis.
Since the coordinates of [tex]\Delta A'B'C'[/tex] gets doubled, so we can say that the [tex]\Delta ABC[/tex] gets dilated by a scale factor of 2.
Thus, the [tex]\Delta ABC[/tex] gets reflection across Y-axis and a dilation by a scale factor of 2.
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