Which half-reaction is most easily oxidized?
Answer: Na^+ + e → Na= -2.71 V (D for plato users)
Answer:
Na+ + e- Na = -2.71 V
Explanation:
We have to remember the nomenclature for redox reactions:
Oxidation:
[tex]M~->~M^++e^-[/tex]
Reduction:
[tex]M^+ + e^-~ ->M[/tex]
So, all the answer options are written as reductions. Therefore the voltage values, in this case, would be the reduction potentials. If we have a higher (positive) potential the compound would be more inclined to a reduction and vice-versa if we have a smaller potential (negative) the compound would be more inclined to oxidation.
In this case, the most negative value is for Na+, so this atom would be more easily oxidized.