Respuesta :
from the question, we know that after 10 seconds are passed the velocity GOES DOWN.
Based on that, we can infer that the acceleration of the arrow will be negative.
in 10 seconds, the velocity goes down 30 meter/second, (65 - 35)
so it would be 30/10 = -3 m/s/s in the same direction of travel
Based on that, we can infer that the acceleration of the arrow will be negative.
in 10 seconds, the velocity goes down 30 meter/second, (65 - 35)
so it would be 30/10 = -3 m/s/s in the same direction of travel
Explanation:
Given that,
Initial velocity of arrow, u = 65 m/s
Final velocity of arrow, v = 35 m/s
Time taken, t = 10 seconds
The acceleration of the arrow is given by the rate of change of velocity per unit time. It is given by :
[tex]a=\dfrac{v-u}{t}[/tex]
[tex]a=\dfrac{35\ m/s-65\ m/s}{10\ s}[/tex]
[tex]a=-3\ m/s^2[/tex]
The arrow in flight is decelerating. Hence, this is the required solution.
