A small circular hole 6.00 mm in diameter is cut in the side of a large water tank, 14.0 m below the water level in the tank. The top of the tank is open to the air. Find the speed at which the water shoots out of the tank
Explanation: To get the speed of the efflux we will use the Torricelli‘s equation which states that the speed of the efflux through a small circular hole is given as v = Square Root 2gh
After inserting the given variables one gets the following efflux velocity v= square root 2 x 9.81 x 14 v= Square Root 276.54 = 16.6 m/s
