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A cylindrical barrel has a radius of 2.1 ft and a height of 14 ft. Doubling which dimension(s) will double the volume of the barrel?

Respuesta :

jcherry99

Answer:

Step-by-step explanation:

r = 2.1 feet

h = 14 feet

V = pi r^2 h

V = 3.14 * 2.1^2 * 14

V = 193.85

Let h = 28 feet

V = pi * r^2 * h

V = 3.14 * 3.2^2 * 28

V = 387.72

If you divide 387.72 by 2 you get 193.86

The difference in the hundreds place comes about because of the rounding that took place.

The answer to your question is you must double the height,