Simplify the complex number.
(8i) (5) (-4-6i)

Answer:
4th option
Step-by-step explanation:
noting that i² = - 1
(8i)(5i)(- 4 - 6i)
= 40i²(- 4 - 6i)
= 40(- 1)(- 4 - 6i)
= - 40(- 4 - 6i) ← distribute parenthesis by - 40
= 160 + 240i
[tex](8i)(5i)(-4-6i)\\\\=40i^2(-4-6i)\\\\=-40(-4-6i)~~~;[i^2=-1]\\\\=160+240i[/tex]