Please help me understand

Answer:
yes
Step-by-step explanation:
The offered ordered pair is a solution if those x- and y-values satisfy both equations. Let's check:
9x +y = 10
9(1) +(1) = 9 +1 = 10 . . . . true
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6x +5y = 11
6(1) +5(1) = 6 +5 = 11 . . . . true
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The ordered pair (x, y) = (1, 1) satisfies both equations, so (1, 1) is a solution to this system.
[tex]\huge\bf\underline{\underline{\pink{A}\orange{N}\blue{S}\green{W}\red{E}\purple{R:-}}}[/tex]
1) Placing (1,1) in equation 9x + y = 10
[tex]:\implies\tt{9(1) + 1 = 10} \\ \\ :\implies\tt{9 + 1 = 10} \\ \\ :\implies\tt{10 = 10} \\ \\ :\implies\tt{lhs = rhs}[/tex]
2) Placing (1,1) in equation 6x + 5y = 11
[tex]:\implies\tt{6(1) + 5(1) = 11} \\ \\ :\implies\tt{6 + 5 = 11} \\ \\ :\implies\tt{11 = 11} \\ \\ :\implies\tt{lhs = rhs}[/tex]