PLEASE HELP
if the exterior angles of two polygons differ by 5 degrees, where one polygon has 'n' sides and the other polygon has (n+1) sides, then find the value of 'n'.

Respuesta :

The interior angle of a polygon, and its exterior angle form a linear pair.

  • The value of n is 8.

Reasons:

The given parameters of the polygon are;

The difference in the exterior angles of the polygon =

Number of sides on one of the polygon = n

Number of sides on the other polygon = n + 1

We get;

The interior angles of a regular polygon are given by the following formula;

[tex]\theta_1 = \mathbf{\dfrac{(n - 2) \times 180^{\circ}}{n}}[/tex]

Which gives;

[tex]\theta_2 = \mathbf{\dfrac{((n + 1) - 2) \times 180^{\circ}}{n + 1}}[/tex]

[tex]\mathbf{\left(180 - \dfrac{(n - 2) \times 180^{\circ}}{n} \right) - \left( 180 - \dfrac{((n + 1) - 2) \times 180^{\circ}}{n + 1} \right)} = 5[/tex]

Simplifying with a graphing calculator gives;

[tex]\dfrac{360}{n^2 + n} = 5[/tex]

5·(n² + n) = 360

5·n² + 5·n - 360 = 0

n² + n - 72 = 0

(n - 8)·(n + 9) = 0

Therefore;

The number of sides on on of the polygon, n = 8

  • The value of n = 8

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