Physics students were modeling the height of a ball once it was dropped from the roof of a 25 story building. The students found that the height in feet, h, of the ball above the ground as a function of the number of seconds, t, since it was dropped was given by h t   300  16t 2 .
From what height was the ball dropped?
To the nearest tenth of a second, determine the time at which the ball hits the ground. Provide evidence from a table to support your answer or solve this algebraically if you recall how to.

Respuesta :

The function of the height of the ball is a quadratic function due to the

acceleration of the ball by gravity.

(a) The height from which the ball was dropped is 300 feet.

(b) The time at which the ball hits the ground is 2.5·√3 seconds.

Reasons:

The given function of the height of the ball in feet is h(t) = 300 - 16·t²

The number of floors on the building = 25 floors (A 25 story  building)

(a) The initial height from which the ball was dropped is given by the

height at time, t = 0 seconds as follows;

The initial height = h(0) = 300 - 16 × 0² = 300

The height from which the ball was dropped, h(0) = 300 feet

(b) At the ground, the height = 0 feet

The time at which the ball hits the ground, is given by h(t) = 0

Therefore;

h(t) = 0 = 300 - 16·

300 = 16·t²

[tex]t^2 = \dfrac{300}{16} =18.75[/tex]

[tex]t = \sqrt{18.75} = \dfrac{5}{2} \cdot \sqrt{3} = 2.5 \cdot \sqrt{3}[/tex]

The time at which the ball hits the ground, t = 2.5·√3 seconds

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