The function of the height of the ball is a quadratic function due to the
acceleration of the ball by gravity.
(a) The height from which the ball was dropped is 300 feet.
(b) The time at which the ball hits the ground is 2.5·√3 seconds.
Reasons:
The given function of the height of the ball in feet is h(t) = 300 - 16·t²
The number of floors on the building = 25 floors (A 25 story building)
(a) The initial height from which the ball was dropped is given by the
height at time, t = 0 seconds as follows;
The initial height = h(0) = 300 - 16 × 0² = 300
The height from which the ball was dropped, h(0) = 300 feet
(b) At the ground, the height = 0 feet
The time at which the ball hits the ground, is given by h(t) = 0
Therefore;
h(t) = 0 = 300 - 16·t²
300 = 16·t²
[tex]t^2 = \dfrac{300}{16} =18.75[/tex]
[tex]t = \sqrt{18.75} = \dfrac{5}{2} \cdot \sqrt{3} = 2.5 \cdot \sqrt{3}[/tex]
The time at which the ball hits the ground, t = 2.5·√3 seconds
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