Question 1
A block with a mass of 2.5 kg slides with a velocity of 3 m/s on a frictionless surface. It hits a horizontal spring with a spring constant of 10 N/m. How much is the
spring compressed when the block stops?

Respuesta :

Answer:

The kinetic energy of the sliding block is =1/2×m×v  

2

 =1/2×4×2  

2

=8 J

Now since there is no friction on the surface then it is a conservative system. So all the energy of the block will be transferred to the spring and will store as a potential energy. Suppose it will compress the spring by an amount of x m. So the potential energy of the spring will be =1/2×k×x  

2

 

Equating there two energies and solving for x, we will get, 1/2×k×x  

2

=8

Or  0.5(400)x  

2

=8

⟹x=0.2 m.  

Explanation: