Respuesta :

DᴀʀᴋPᴀʀᴀᴅᴏx

[tex]▪▪▪▪▪▪▪▪▪▪▪▪▪  {\huge\mathfrak{Answer}}▪▪▪▪▪▪▪▪▪▪▪▪▪▪[/tex]

Let's solve ~

  • [tex]7 {x}^{2} - 42x = 0[/tex]

  • [tex]7x(x - 6) = 0[/tex]

There are two cases here, Either 7x = 0 or x - 6 = 0

So, let's solve for both of them ~

Case #1 - when 7x = 0

  • [tex]x = \dfrac{0}{7} [/tex]

  • [tex]x = 0[/tex]

Case #2 - when x - 6 = 0

  • [tex]x = 0 + 6[/tex]

  • [tex]x = 6[/tex]

So, the Correct choices are ~

  • [tex] \boxed{ \boxed{x = 0} \: and \: \boxed{x = 6}}[/tex]

Sᴘᴀᴄᴇ7

[tex]\sf \longmapsto7x {}^{2} −42x=0[/tex]

[tex]\sf \longmapsto7x(x−6)=0[/tex][Factor left side of equation]

[tex]\sf \longmapsto7x=0 or x−6=0[/tex][Set factors equal to 0]

[tex]\sf \longmapsto \: x=0 or x=6[/tex]

So, Correct Options are:

[tex]\sf \longmapsto \: x = 0 \: and \: x = 6[/tex]