Answer:
2.2V; 6.8V
Explanation:
That's a classic voltage divider. The voltage drop across the [tex]2.2 k\Omega[/tex] is [tex]V_{2.2} = {{2.2} \over {2.2+6.8}} 9V = 2.2V[/tex]. The drop across the second resistor is what's left, or [tex]6.8V[/tex]
Else, the two resistors behave like a single resistor of [tex]9k\Omega[/tex] (the sum of the two, since it's a series). It means that across them flows a 1mA current (Ohm first law), from which you can calculate the drop across each resistor by multiplying the current by each resistence.
