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fe (s) + s (l) --> fes (s) in the experiment above, 7.62 g of fe are allowed to react with 8.67 g of s.how much fes is formed?

Respuesta :

yashjaglan012

Answer:

16.29g

Acc to law of conservation of mass

MASS OF REACTANT = MASS OF PRODUCT SIDE

m (fe) + m(s) = m(fes)

7.62 + 8.67 = m(FeS)

16.29g = m (FeS)

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