Hydrogen selenide (H2Se) reacts with water according to the following equation.

H2Se + H2O → SeH– + H3O+

In three to five sentences, identify the acid, base, conjugate acid, and conjugate base in this reaction. Use patterns in the periodic table to explain why the substances you identified acted as the acid and the base in this reaction.

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18-10-2021
Biology

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Hydrogen selenide (H2Se) reacts with water according to the following equation.

H2Se + H2O → SeH– + H3O+

In three to five sentences, identify the acid, base, conjugate acid, and conjugate base in this reaction. Use patterns in the periodic table to explain why the substances you identified acted as the acid and the base in this reaction.

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pstnonsonjoku pstnonsonjoku · Answer 1 · 2021-10-29T10:33:15+02:00

The acid is H2Se, the base is H2O, the conjugate acid is H3O+, the conjugate base is SeH–.

The reaction equation is as follows;

H2Se + H2O → SeH– + H3O+

The acid is the specie that donates a proton while the base is the specie that accepts the proton.

The specie formed from the acid after it donates a proton is called the conjugate base while the specie formed from the base after accepting a proton from the acid is called the conjugate acid.

From the reaction equation, we can see that the acid is H2Se, the base is H2O. The conjugate acid is H3O+ while the conjugate base is SeH– .

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