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A woman has a total of $ 9,000 to invest. She invests part of the money in an account that pays 11 % per year and the rest in an account that pays 12 % per year. If the interest earned in the first year is $ 1040, how much did she invest in each account?

Respuesta :

interest + interest      = total interest

0.08*x   + 0.09*(9000-x) = 750    dollars

0.08x + 810 - 0.09x = 750

-0.01x = 750 - 810 = -60  ====>  x = [tex]\frac{-60}{-0.01}[/tex] = 6,000

Answer.  $6000 was invested at 8%.  The rest   9000-6000 = 3000 dollars were invested at 9%.

Check.   0.08*6000 + 0.09*3000 = 480 + 270 = 750 dollars.  

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