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Two naturally occurring isotopes of aluminum exist, Al-26 and Al-27. Aluminum's atomic mass is -26.98 u. What can you conclude about the relative abundance of each isotope?​

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Eduard22sly

The abundance of each isotope are:

1. The abundance of isotope Al-26 is 2%

2. The abundance of isotope Al-27 is 98%

Let isotope Al-26 be A

Let isotope Al-27 be B

From the question given above, the following data were obtained:

Atomic mass of Al = 26.98 u.

For A (isotope Al-26):

Mass of A = 26

Abundance of A (A%) =?

For A (isotope Al-27):

Mass of A = 27

Abundance of B (B%) = 100 – A%

Atomic mass = [(Mass of A × A%)/100] + [(Mass of B × B%)/100]

26.98 = [(26 × A%)/100] + [(27 × (100 – A%))/100]

26.98 = 0.26A% + 27 – 0.27A%

Collect like terms

26.98 – 27 = 0.26A% – 0.27A%

–0.02 = –0.01A%

Divide both side by –0.01

A% = –0.02 / –0.01

A% = 2%

Abundance of B (B%) = 100 – A%

Abundance of B (B%) = 100 – 2%

Abundance of B (B%) = 98%

From the calculations made above, we can conclude that;

1. The abundance of isotope Al-26 is 2%

2. The abundance of isotope Al-27 is 98%

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