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The federal government defines vinegar as a solution with a minimum of 40 grams of acetic acid per liter of vinegar. Calculate the mass percentage of acetic acid that must be vinegar. Assume vinegar has a density of 1.00g/mL

Respuesta :

Taking into account the definition of mass percentage and density,  the mass percentage of acetic acid that must be vinegar is 3.85%.

The mass percentage (or weight) of a solution is a way of representing the concentration of an element in a compound or a component in a mixture that indicates the number of grams of solute that there are per 100 grams of solution.

The expression for its calculation is:

[tex]mass percentage= \frac{solute mass}{solute mass + solvent mass} x100= \frac{solute mass}{solution mass} x100[/tex]

In this case, you have a solution with a minimum of 40 grams of acetic acid per liter of vinegar. The vinegar has a density of 1.00g/mL.

Considering that the density is a quantity that allows us to measure the amount of mass in a certain volume of a substance, the mass of vinegar can be calculated as:

[tex]1 \frac{g}{mL} =\frac{mass of vinegar}{1000 mL}[/tex]

where 1000 mL= 1 L

Solving:

mass of vinegar= 1[tex]\frac{g}{mL}[/tex]× 1000 mL

mass of vinegar= 1000 g

So, you know:

  • solute mass= 40 grams
  • solvent mass= 1000 grams

Then, the mass percentage can be calculated as:

[tex]mass percentage= \frac{40 grams}{40 grams + 1000 grams} x100[/tex]

[tex]mass percentage= \frac{40 grams}{1040 grams} x100[/tex]

mass percentage= 3.85 %

Finally, the mass percentage of acetic acid that must be vinegar is 3.85%.

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