Respuesta :
Taking into account the definition of mass percentage and density, the mass percentage of acetic acid that must be vinegar is 3.85%.
The mass percentage (or weight) of a solution is a way of representing the concentration of an element in a compound or a component in a mixture that indicates the number of grams of solute that there are per 100 grams of solution.
The expression for its calculation is:
[tex]mass percentage= \frac{solute mass}{solute mass + solvent mass} x100= \frac{solute mass}{solution mass} x100[/tex]
In this case, you have a solution with a minimum of 40 grams of acetic acid per liter of vinegar. The vinegar has a density of 1.00g/mL.
Considering that the density is a quantity that allows us to measure the amount of mass in a certain volume of a substance, the mass of vinegar can be calculated as:
[tex]1 \frac{g}{mL} =\frac{mass of vinegar}{1000 mL}[/tex]
where 1000 mL= 1 L
Solving:
mass of vinegar= 1[tex]\frac{g}{mL}[/tex]× 1000 mL
mass of vinegar= 1000 g
So, you know:
- solute mass= 40 grams
- solvent mass= 1000 grams
Then, the mass percentage can be calculated as:
[tex]mass percentage= \frac{40 grams}{40 grams + 1000 grams} x100[/tex]
[tex]mass percentage= \frac{40 grams}{1040 grams} x100[/tex]
mass percentage= 3.85 %
Finally, the mass percentage of acetic acid that must be vinegar is 3.85%.
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