What is the awnser the the math problem

Answer:
[tex] \tan(x) = \frac{8}{ \sqrt{23} } [/tex]
Step-by-step explanation:
[tex] {a}^{2} + {b}^{2} = {c}^{2} \\ {a}^{2} + ( { \sqrt{23} })^{2} =( { \sqrt{87} })^{2} \\ {a}^{2} + 23 = 87 \\ {a}^{2} = 87 - 23 \\ {a}^{2} = 64 \\ a = 8[/tex]
tan x = opposite / adjacent
[tex] \tan(x) = \frac{8}{ \sqrt{23} } [/tex]