Respuesta :
[tex]▪▪▪▪▪▪▪▪▪▪▪▪▪ {\huge\mathfrak{Answer}}▪▪▪▪▪▪▪▪▪▪▪▪▪▪[/tex]
Let's solve :
- [tex](b + 1)3 - (b - 1)[/tex]
- [tex]3b + 3 - b + 1[/tex]
- [tex]2b + 4[/tex]
Answer:
Step-by-step explanation:
i think he is asking
(b+1)³-(b-1)
=b³+1³+3b*1(b+1)-b+1
=b³+1+3b²+3b-b+1
=b³+3b²+2b+2