[tex]\\ \sf\longmapsto AM=\dfrac{1}{2}BC[/tex]
[tex]\\ \sf\longmapsto AM=BM=CM[/tex]
- All points are equidistant from M
If it becomes a inscribed triangle
- A,B,C will create a arc of 180°
[tex]\\ \sf\longmapsto arcABC=180°[/tex]
- The measure of inscribed angle is half the inscribed arc
[tex]\\ \sf\longmapsto <BAC=\dfrac{1}{2}arc ABC[/tex]
[tex]\\ \sf\longmapsto <BAC=\dfrac{1}{2}180°[/tex]
[tex]\\ \sf\longmapsto <BAC=90°[/tex]
Hence ABC is a right angled triangle (Verified)
