Respuesta :
The rectangle with the largest area will always be a square.
40/4=10
A square with side lengths of 10 units yields the largest area.
A=s^2
A=10^2
A=100 square units
A=9*11=99 square units
A=8*12=96 square units
and so on...
If you need proof...
P=2l+2w
40=2l+2w
20=l+w
20-w=l
A=lw
A=(20-w)w
A=20w-w^2
this is a parabola opening downward; it has a maximum at its vertex, (h,k)
use h=-b/2a
h=-20/-2=10
Answer:
[tex]Perimeter \: of \: the \: rectangle =40 cm[/tex]
[tex]Width \: of \: rectangle =1 cm[/tex]
[tex]Area = [2 *1] + [2 * 40] =2 + 80 =82 cm - the \: largest \: area.[/tex]
Sorry If it is wrong........
