Which equation justifies why seven to the one-third power equals the cube root of seven?
[tex]7^1/3 = \sqrt[3]{7}[/tex]

Answer:
Third one
Step-by-step explanation:
The only equation that is even true is the third one.
If the cube of a number is x, then cube root of x is that number.
So the cube of 7^(1/3) is (7^(1/3))^3.
By law of exponents, we have (7^(1/3))^3=7^(1/3×3)=7^1=7.
So the cube of 7^(1/3) is 7, so the cube root of 7 is 7^(1/3).