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Holly chooses seven out of nine plants for the front of her house with the remaining plants to be used on the side of the house. if order does not matter, in how many ways can she choose the plants for the front of the house? 7 9 21 36

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MissPhiladelphia
A formula for the number of possible combinations of r objects from a set of n objects. For this, order is not important. We calculate it as follows:

nCr
9C7
36 <-------last option
facundo3141592

The total number of different combinations of thr 7 plants is 36.

In how many ways can Holly select the plants?

If we have a set of N elements, the number of different sets of k elements that we can make out of the N elements is given by:

[tex]C(N, k) = \frac{N!}{(N - k)!*k!}[/tex]

In this case, we have N = 9, the total number of plants, k = 7, the number that we need to select.

Replacing that we get:

[tex]C(9, 7) = \frac{9!}{(9 - 7)!*7!} = \frac{9*8}{2} = 36[/tex]

This means that the 7 plants can be selected in 36 different ways.

If you want to learn more about combinations, you can read:

https://brainly.com/question/251701

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