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A ball rolls off of a table (take v0 as 0m/s) that is 1.25m tall. How long does it take for the ball to hit the floor?

Respuesta :

Mazia
Let
h=height of table= 1.25m
g=acceleration due to gravity= 9.8m/s^2
t=time taken=?

Solution
  h   =(vi)(t)+1/2(g)(t^2)
1.25=(0)(t)+1/2(9.8)(t^2)
t^2  = 0.255
 t.    = 0.5s

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