Rubidium has an atomic number of 37 and a mass number of 85. How many protons, neutrons, and electrons does an ion of rubidium with a 1+ charge have?(1 point)

A ) 37 protons, 48 neutrons, and 36 electrons

B ) 48 protons, 37 neutrons, and 36 electrons

C ) 37 protons, 48 neutrons, and 38 electrons

D) 48 protons, 37 neutrons, and 38 electrons

An atom has protons, neutrons, and electrons. The protons and neutrons are in the nucleus of the atom, while the electrons are located in the orbital.

An ion of rubidium with a 1+ charge have (option A)

37 protons
48 neutrons
36 electrons

Given that:

[tex]A \to[/tex] Atomic number

[tex]M \to[/tex] Mass number

So:

[tex]A = 37[/tex]

[tex]M = 85[/tex]

The number of protons is the atomic number (i.e. 37)

The number of neutrons (N) is calculated as follows:

[tex]N = M - A[/tex]

[tex]N = 85- 37[/tex]

[tex]N = 48[/tex]

From the question, we understand that ion is 1+ charge.

This means that we subtract 1 from the atomic number to get the number of electrons (E) i.e.

[tex]E = A -1[/tex]

[tex]E =37 -1[/tex]

[tex]E =36[/tex]

Hence, an ion of rubidium with a 1+ charge have (option A)

37 protons
48 neutrons
36 electrons

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