contestada

A
1
-4
-3
-2
-1
0
00
-1
-2.
The distance AB rounded to the
nearest tenth = [?]
Hint: d = V(x2 – x1)2 + (y2 - yı)2

A 1 4 3 2 1 0 00 1 2 The distance AB rounded to the nearest tenth Hint d Vx2 x12 y2 yı2 class=

Respuesta :

okiwix

Answer:

2.8

Step-by-step explanation:

use the distance formula in the picture:

[tex]\sqrt{(-1-(-3))^2+((-1)-1)^2} = \sqrt{2^2+(-2)^2} = \sqrt{4+4} = \sqrt{8} = 2\sqrt{2} = 2.8284[/tex]

Answer:

AB ≈ 2.8

Step-by-step explanation:

Calculate the distance d using the distance formula

d = [tex]\sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2 }[/tex]

with (x₁, y₁ ) = A (- 3, 1) and (x₂, y₂ ) = B (- 1, - 1)

d = [tex]\sqrt{(-1-(-3))^2+(-1-1)^2}[/tex]

  = [tex]\sqrt{(-1+3)^2+(-2)^2}[/tex]

  = [tex]\sqrt{2^2+4}[/tex]

  = [tex]\sqrt{4+4}[/tex]

  = [tex]\sqrt{8}[/tex]

  ≈ 2.8 ( to the nearest tenth )

 

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