Answer:
$6.50
Step-by-step explanation:
Let the cost of a bowl and a jug be $b and $j respectively.
3b +j= 13.70 -----(1)
j= b +4.10 -----(2)
Substitute (2) into (1):
3b +b +4.10= 13.70
4b +4.10= 13.70 (simplify)
4b= 13.70 -4.10 (-4.10 on both sides)
4b= 9.60
b= 9.60 ÷4 (÷4 on both sides)
b= 2.40
Substitute b= 2.40 into (2):
j= 2.40 +4.10
j= 6.50
Thus, the jug costs $6.50.
