Answer:
[tex]f(x) = x^4 + 9x^3 + 27x^2 + 27x[/tex]
Step-by-step explanation:
Zeros of a function:
Given a polynomial f(x), this polynomial has roots [tex]x_{1}, x_{2}, x_{n}[/tex] such that it can be written as: [tex]a(x - x_{1})*(x - x_{2})*...*(x-x_n)[/tex], in which a is the leading coefficient.
- 3 as a zero of multiplicity 3
So
[tex]f(x) = (x - (-3))^3 = (x + 3)^3 = x^3 + 9x^2 + 27x + 27[/tex]
0 as a zero of multiplicity 1.
So
[tex]f(x) = x(x^3 + 9x^2 + 27x + 27) = x^4 + 9x^3 + 27x^2 + 27x[/tex]
(Use 1 for the leading coefficient.)
Multiply the polynomial by 1, so it stays the same. The polynomial in expanded form is:
[tex]f(x) = x^4 + 9x^3 + 27x^2 + 27x[/tex]
