A bullet is fired vertically upward a velocity of 80m/s to what height will the bullet rise above the point of projection

Question

contestada

Respuesta :

angrykai23 angrykai23 · Answer 1 · 2021-07-16T11:49:45+02:00

Answer:

The bullet will rise 320 meters above the point of projection.

Explanation:

Assuming that air friction is negligent we can use the kinematic equation:

[tex]v_{2} ^2=v_{1} ^2+2(-a)d\\0\frac{m^2}{s^2} =6400\frac{m^2}{s^2} +2(-10\frac{m}{s^2} )d\\-6400\frac{m^2}{s^2} =(-20\frac{m}{s^2}) d\\320m=d[/tex]

*acceleration is negative (-a) as it is acting in the opposite direction of the motion of the bullet.*

Answer Link

priyankatutor priyankatutor · Answer 2 · 2021-12-29T06:30:57+01:00

The bullet rises to a height of 3600 m if a bullet is fired upward with a velocity of 80 m/s.

Assume the air friction is negligible, the kinematic equation:

[tex]v_f^2 = v_i^2 +2(-a) d[/tex]

Where,

[tex]v_i^2[/tex] - iinitial velocity = 80 m/s

[tex]v_f^2[/tex]- final velocity = 0

[tex]d[/tex]- distance= ?

[tex]a[/tex]- gravitational acceleration = 9.8 m/s² = 10 m/s²

Put the values in the formula,

[tex]\begin {aligne} 0 = (80)^2 + 2 (10)^2 d\\\\d = \dfrac {6400}{ 200}\\\\d &= 3600 \rm \ m\end {aligne}\\[/tex]

Therefore, the bullet rises to a height of 3600 m if a bullet is fired upward with a velocity of 80 m/s.

To know more about kinematic equation:

https://brainly.com/question/5955789