Complete Question
How many moles of magnesium oxide are produced by the reaction of 1.82 g of magnesium nitride with 17.73 g of water? Mg3N2 + 3H20 + 2NH3 + 3MgO
Answer:
[tex]Moles\ of\ MgO = 0.054 mol[/tex]
Explanation:
From the question we are told that:
Reaction Formula:
[tex]Mg_3N_2 + 3H_2_O => 2NH_3 + 3MgO[/tex]
[tex]Mass Mg_3N_2 =1.82g[/tex]
[tex]H_20=17.73g[/tex]
Therefore
[tex]Moles\ of\ Mg_3N_2 =\frac{1.82g}{100.25}[/tex]
[tex]Moles\ of\ Mg_3N_2 =0.0180 mol[/tex]
Generally
[tex]Moles\ of\ H_20 =\frac{17.73g}{18.015}[/tex]
[tex]Moles\ of\ H_20 = 0.9841[/tex]
Therefore
[tex]Moles\ of\ MgO =0.0180 mol * (3 mol of MgO)[/tex]
[tex]Moles\ of\ MgO = 0.054 mol[/tex]
Answer:
0.0182 mole of magnesium oxide, MgO
Explanation:
We'll begin by calculating the number of mole in 1.82 g of magnesium nitride, Mg₃N₂. This can be obtained as follow:
Mass of Mg₃N₂ = 1.82 g
Molar mass of Mg₃N₂ = (3×24) + (2×14)
= 72 + 28
= 100 g/mol
Mole of Mg₃N₂ =?
Mole = mass / molar mass
Mole of Mg₃N₂ = 1.82 / 100
Mole of Mg₃N₂ = 0.0182 mole
Finally, we shall determine the number of mole of magnesium oxide, MgO produced from the reaction. This can be obtained as follow:
Mg₃N₂ + 3H₂O –> 3MgO + 2NH₃
From the balanced equation above,
3 moles of Mg₃N₂ reacted to 3 moles of MgO.
Therefore, 0.0182 mole of Mg₃N₂ will also react to produce 0.0182 mole of MgO.
Thus, 0.0182 mole of magnesium oxide, MgO was obtained from the reaction.
