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A right triangle has side lengths 5, 12 and 13 as shown below use these lengths to find cosB tan B and sin B
PLZ SOMEONE HELP BRAINLIEST

A right triangle has side lengths 5 12 and 13 as shown below use these lengths to find cosB tan B and sin B PLZ SOMEONE HELP BRAINLIEST class=

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Step-by-step explanation:

cosB = [tex]\frac{adjacent}{hypotenuse}[/tex] = [tex]\frac{BC}{AB}[/tex] = [tex]\frac{5}{13}[/tex]

tanB = [tex]\frac{opposite}{adjacent}[/tex] = [tex]\frac{AC}{BC}[/tex] = [tex]\frac{12}{5}[/tex]

sinB = [tex]\frac{opposite}{hypotenuse}[/tex] = [tex]\frac{AC}{AB}[/tex] = [tex]\frac{12}{13}[/tex]

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