Answer:
[tex]E=5\times 10^{-5}\ J[/tex]
Explanation:
Given that,
A spring is compressed by 0.1 cm or 0.001 m
The spring constant of the spring, k = 100 N/m
The elastic potential energy in the spring is given by :
[tex]E=\dfrac{1}{2}kx^2\\\\E=\dfrac{1}{2}\times 100\times 0.001^2\\\\E=5\times 10^{-5}\ J[/tex]
So, the elastic potential energy of the spring is equal to [tex]5\times 10^{-5}\ J[/tex].
