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A violinist is tuning her violin to 440Hz. She plays the note while listening to an electronically generated tone and hears 3Hz, which increases to 4Hz when she tightens the violin. What was the frequency of the note played by the violin when she heard the 3 Hz beats

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okpalawalter8

Answer:

[tex]X=438Hz[/tex]

Explanation:

From the question we are told that:

Beat Frequency [tex]Fb=440Hz[/tex]

Actual Frequency [tex]F_a=3Hz[/tex]

Generally the equation for Frequency Heard X is mathematically given by

[tex]X=beat\ frequency\ +\ actual\ frequency[/tex]

[tex]X=F_a+Fb[/tex]

[tex]X= 440Hz+3Hz[/tex]

[tex]X=438Hz[/tex]

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