contestada

A 0.15 M solution of BaCl2 contains: Group of answer choices 0.30 M Ba2 ions and 0.30 M Cl- ions. 0.15 M Ba2 ions and 0.15 M Cl- ions. 0.30 M Ba2 ions and 0.15 M Cl- ions. 0.15 M Ba2 ions and 0.30 M Cl- ions. none of the above

Respuesta :

maacastrobr

Answer:

0.15 M Ba⁺² ions and 0.30 M Cl⁻ ions

Explanation:

The dissociaton of barium chloride is as follows:

BaCl₂ → Ba²⁺ + 2Cl⁻

By observing the stoichiometric coefficients, we can tell that the number of moles of Ba²⁺ is the same as the number of moles of BaCl₂, while the number of moles of Cl⁻ is the double of that.

Otras preguntas