Answer:
a) The area of the triangle AQB is 43 square centimeters.
b) The length of the line segment AQ is approximately 14.866 centimeters.
Step-by-step explanation:
a) The procedure consist in subtracting the areas of triangles APQ, ASB and BRQ of the area the rectangle, that is to say:
[tex]A = (9\,cm)\cdot (14\,cm) - \frac{1}{2}\cdot (5\,cm)\cdot (14\,cm) - \frac{1}{2}\cdot (8\,cm)\cdot (9\,cm) -\frac{1}{2}\cdot (4\,cm) \cdot (6\,cm)[/tex]
[tex]A = 43\,cm^{2}[/tex]
The area of the triangle AQB is 43 square centimeters.
b) The length of the line segment AQ is determined by Pythagorean Theorem:
[tex]AQ = \sqrt{AP^{2}+PQ^{2}}[/tex] (1)
[tex]AQ = \sqrt{(5\,cm)^{2}+(14\,cm)^{2}}[/tex]
[tex]AQ \approx 14.866\,cm[/tex]
The length of the line segment AQ is approximately 14.866 centimeters.
