Answer:
a = 3.27 m/s²
T = 275 N
Explanation:
Given that:
Mass m₁ = 42.p0 kg
Mass m₂ = 21.0 kg
Consider both masses to be in a whole system, then:
The acceleration can be determined as:
[tex](m_1+m_2)a = g(m_1-m_2)[/tex]
Making acceleration the subject in the above formula;
[tex]a =\dfrac{g(m_1-m_2)}{(m_1+m_2)}[/tex]
[tex]a =\dfrac{9.8(42.0-21.0)}{(42.0+21.0)}[/tex]
[tex]a =\dfrac{9.8(21.0)}{(63.0)}[/tex]
[tex]a =\dfrac{205.8}{(63.0)}[/tex]
a = 3.27 m/s²
in the string, the tension is calculated using the formula:
[tex]T = \dfrac{2m_1m_2g}{(m_1+m_2)}[/tex]
[tex]T = \dfrac{2(42)(21)(9.81)}{(42+21)}[/tex]
[tex]T = \dfrac{17304.84}{63}[/tex]
T = 274.68 N
T ≅ 275 N
