Simplify (sin^2 0+cos^2 0) (sin 0+cos 0)
Can someone help? I don’t understand.

Answer:
C) [tex]sin\theta+cos\theta[/tex]
Step-by-step explanation:
[tex](sin^2\theta+cos^2\theta)(sin\theta+cos\theta)[/tex]
[tex]sin\theta+cos\theta[/tex]
Recall the Pythagorean Trigonometric Identity where [tex]sin^2\theta+cos^2\theta=1[/tex], so [tex]1(sin\theta+cos\theta)=sin\theta+cos\theta[/tex]
Answer:
C
Step-by-step explanation:
To start this problem off, we should know an important trig rule:
[tex]\sin^2(\theta)+\cos^2(\theta)=1[/tex]
From here, it is simple:
[tex](\sin^2(\theta)+\cos^2(\theta))(\sin(\theta)+\cos(\theta))=\\1(\sin(\theta)+\cos(\theta))=\\\sin(\theta)+\cos(\theta)[/tex]
C
I hope this helps! Let me know if you have any questions :)