Answer:
The ratio of the electrostatic force to the gravitational force between the electrons is 4.181 x 10⁴²
Explanation:
Given;
charge of electron, Q = 1.602 x 10⁻¹⁹ C
mass of an electron, m = 9.1 x 10⁻³¹ kg
distance between the two electrons, r = 6.64 x 10⁻¹¹ m
The electrostatic force between the electrons is calculated using Coulomb's law;
[tex]F_e = \frac{kQ^2}{r^2} \\\\F_e = \frac{(9\times 10^9)(1.602 \times 10^{-19})^2}{(6.64 \times 10^{-11})^2} \\\\F_e = 5.239 \times 10^{-8} \ N[/tex]
The gravitaional force between the electrons is calculated as;
[tex]F_g = \frac{Gm^2}{r^2} \\\\F_g = \frac{(6.67\times 10^{-11})(9.1 \times 10^{-31})^2}{(6.64\times 10^{-11})^2} \\\\F_g = 1.253 \times 10^{-50} \ N[/tex]
The ratio of the electrostatic force to the gravitational force between the electrons;
[tex]\frac{F_e}{F_g} = \frac{5.239\times 10^{-8}}{1.253 \times 10^{-50}} = 4.181 \times 10^{42}[/tex]
