Given f(x) = 3 and g(x) = cos(x). What is Limit of left-bracket f (x) minus g (x) right-bracket as x approaches negative pi?
2
3
4
DNE

We apply limits concepts to solve this question. Since the functions have no discontinuity, we just replace the values, and 4 is the answer.
Functions:
The functions are:
[tex]f(x) = 3[/tex]
[tex]g(x) = \cos{x}[/tex]
Limit:
[tex]\lim_{x \rightarrow -\pi} [f(x) - g(x)] = \lim_{x \rightarrow -\pi} [3 - \cos{x}] = 3 - \cos{\pi} = 3 - (-1) = 3 + 1 = 4[/tex]
Thus, 4 is the answer to this question.
For more on limits, you can check https://brainly.com/question/23145093