A bag contains 4 blue and 6 green marbles. Two marbles are selected at random from the bag. find each of the following probabilities round your answer two decimals if needed.

Answer: here you go
Step-by-step explanation:
1st probability: green first then blue second: 6/10*4/9 = 24/90 or about 0.27
2nd probability: blue first then green second: 4/10*6/9 = same as first answer (about 0.27)
Each and every probability was found using probability theory.
Number of blue balls = 4
Number of green balls =6
Total number of balls =10
Probability is the measure of the likelihood of occurrences.
A) Without replacement:
P(green first) = 6/10
Number of balls left =9
Number of blue balls =4
So, P(blue second) = 4/9
Total probability = 6/10 * 4/9 = 4/15
P(blue first) = 4/10
Number of balls left =9
Number of green balls =6
So, P(blue second) = 6/9
Total probability = 4/10 * 6/9 = 4/15
B) With replacement:
P(blue first) =4/10
Number of balls left =10
Number of green balls = 6
So, P(green second) = 6/10
Total probability = 4/10 * 6/10 = 6/25
P(green first) =6/10
Number of balls left =10
Number of blue balls = 4
So, P(green second) = 4/10
Total probability = 6/10 * 4/10 = 6/25
Thus, each and every probability was found using probability theory.
To get more about probability visit:
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